Little changes on Colombian Programming Contest solutions.
[andmenj-acm.git] / 12317 - Document Compression / ana.cpp
blobc6eb0b09966bf25cc72bd53993b8a8a61867328f
1 // Code written by Ana Echavarría
2 using namespace std;
3 #include <iostream>
4 #include <vector>
5 #include <queue>
7 // Maximum base size is 2^16 - 1
8 const int maxN = 1 << 16;
9 int length [maxN];
11 int main(){
12 int nBases, nDocs;
13 while(cin >> nBases >> nDocs){
14 if (nBases == 0 and nDocs == 0) break;
15 //Initialize length
16 for (int i = 0; i < maxN; i++) length[i] = -1;
17 // Read the bases
18 vector <int> bases(nBases, 0);
19 for (int b = 0; b < nBases; b++){
20 int k; cin >> k;
21 while(k--){
22 int num; cin >> num;
23 bases[b] |= 1 << (num-1);
26 // Read the documents
27 vector <int> docs(nDocs, 0);
28 for (int d = 0; d < nDocs; d++){
29 int k; cin >> k;
30 while(k--){
31 int num; cin >> num;
32 docs[d] |= 1 << (num-1);
35 // Start BFS
36 queue <int> q;
37 q.push(0);
38 length[0] = 0;
39 while(q.size() > 0){
40 int curr = q.front();
41 q.pop();
42 for (int i = 0; i < bases.size(); i++){
43 // Build next document
44 int next = curr | bases[i];
45 // Check if it has not been visited yet
46 if (length[next] >= 0) continue;
47 length[next] = length[curr] + 1;
48 q.push(next);
51 // Print answers
52 for (int d = 0; d < docs.size(); d++){
53 int document = docs[d];
54 if (length[document] >= 0) cout << length[document];
55 else cout << 0;
56 if (d < docs.size() - 1) cout << " ";
57 else cout << endl;
62 return 0;